#Construct segment trisector gsp5 how to

The opposite side is called the () of the triangle The line between the vertex and the perpendicular foot is called the () of the triangle. Make a vertical line from a vertex of a triangle to its opposite side. The line between the vertex and the perpendicular foot is called the triangle's () and the opposite side is called the triangle's Generally, N equal parts only need to fill in 360 ° / n If you want six equal parts, you only need to fill in 60 ° in the 'fixed angle' above and operate for 5 times if you want twelve equal parts, you need to fill in 30 ° and operate for 11 times Then a, a 'and a 'divide the circle into three equal parts

Continue the second step with a 'and get a“ Select point a, click the transform menu, and choose rotate, fill in 120 ° under 'fixed angle' of 'rotation parameters' in the pop-up window, and then click OK to get a trisection point a 'ģ. Double click the center of the circle, and then take any point a in the circleĢ. How can Geometer's Sketchpad find the third, sixth and twelfth equinox of a circle?ġ. Click 'deep iteration', and then click 'point B' to confirm This means that 'iteration' becomes 'deep iteration'. Then click 'transform' and hold down the 'shift' key at the same time. Create a new parameter n = 5, select points a and N, (pay attention to the order). Double click the center of the circle, then select point a, point 'transform → rotate', enter 60 ° and point 'OK' to get point BĤ.

#Construct segment trisector gsp5 how to

How to draw inscribed regular hexagon of circle in Geometer's SketchpadĢ. Select a line segment and a point, construct - draw circle with center and radius In the Geometer's Sketchpad, how to make a line segment equal to the radius of a circle, and change the length of the line segment, the radius of the circle also changesĭraw a line segment and a point. Connect C and circle with line segment, That's what you want Then, draw a circle with C as the center and D as the radius. The angle is arbitrary and the length is the distance just measured. Then, select two endpoints except the center (the flashing point is the center when the point is zoomed), measure → distance, and then build another point C, transform → translation.

How to draw two 3:2 straight lines with the Geometer's Sketchpadįirst, draw a line segment and divide it into three equal parts (transform → zoom). Select only midpoint A and m, and 'construct' and 'track' The middle point m of AB is constructed by Ctrl + M Ĥ. Draw any point B, select only two points a and B, and construct line segment with 'Ctrl + L' ģ. First draw a circle, draw a point a on the circle Ģ. Select point a and point m to construct the trajectoryġ. Then circle O is the range, a is the active point and M is the passive point In the Geometer's Sketchpad, how to determine a fixed point and how to create a trajectory: the midpoint trajectory of a point a and any point B on circle O:Ĭonstruct line segment AB, construct midpoint m of line segment How to construct tracks in Geometer's Sketchpad Note that the major axis of the ellipse is not necessarily horizontal or verticalĪt least three major axes are horizontal or vertical How many points can determine an ellipse? Given these points, how to make an ellipse on the Geometer's Sketchpad? Hide the result of the measure, and the calculated value will replace the measure value. Then create a calculation, calculate the measure value △ 1cm, and the result is that only the number of the measure is retained, and the unit is gone. For example, a = 2.0 is directly displayed Should I draw it like this?įirst draw the circle, then select the two ends of the arc you want to draw on the circle (note that you should select it in the counterclockwise direction), and then use 'construction'Įxcuse me, I have measured the length of a line segment in the Geometer's Sketchpad, but I want to hide the unit and only show the number,īecause pulling a line segment, its length will change, but it doesn't need that unit. I want to draw the part of the superior arc. I want to use the Geometer's Sketchpad to draw an arc on a circle, but I can only draw the part of the inferior arc. I use the Geometer's Sketchpad to draw an arc on a circle. So when we encounter this kind of abnormal integral, we will make a mistake, because it involves the limit problem Geometer's Sketchpad is approximate, that is, take many points from 0 to 1 to calculate their function values and add them up Is the definite integral of inverse proportional function from 0 to 1 positive infinity? Why does the Geometer's Sketchpad show 11 / 3 of the answer?